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nmode's Git Repositories - Rnaught/blob - R/IDEA.R
3 #' This function implements a least squares estimation method of R0 due to Fisman et al. (PloS One, 2013).
4 #' See details for implementation notes.
6 #' This method is closely related to that implemented in \code{ID}. The method is based on an incidence decay model.
7 #' The estimate of R0 is the value which minimizes the sum of squares between observed case counts and cases counts
8 #' expected under the model.
10 #' This method is based on an approximation of the SIR model, which is most valid at the beginning of an epidemic.
11 #' The method assumes that the mean of the serial distribution (sometimes called the serial interval) is known.
12 #' The final estimate can be quite sensitive to this value, so sensitivity testing is strongly recommended.
13 #' Users should be careful about units of time (e.g., are counts observed daily or weekly?) when implementing.
15 #' @param NT Vector of case counts.
16 #' @param mu Mean of the serial distribution. This needs to match case counts in time units. For example, if case counts
17 #' are weekly and the serial distribution has a mean of seven days, then \code{mu} should be set to one. If case
18 #' counts are daily and the serial distribution has a mean of seven days, then \code{mu} should be set to seven.
20 #' @return \code{IDEA} returns a single value, the estimate of R0.
23 #' ## ===================================================== ##
24 #' ## Illustrate on weekly data ##
25 #' ## ===================================================== ##
27 #' NT <- c(1, 4, 10, 5, 3, 4, 19, 3, 3, 14, 4)
28 #' ## obtain Rhat when serial distribution has mean of five days
29 #' IDEA(NT=NT, mu=5/7)
30 #' ## obtain Rhat when serial distribution has mean of three days
31 #' IDEA(NT=NT, mu=3/7)
33 #' ## ========================================================= ##
34 #' ## Compute Rhat using only the first five weeks of data ##
35 #' ## ========================================================= ##
37 #' IDEA(NT=NT[1:5], mu=5/7) # serial distribution has mean of five days
40 IDEA
<- function(NT
, mu
) {
42 print("Warning: length of NT should be at least two.")
52 IDEA1
<- sum(y2
) * sum(y1
) - sum(s
) * sum(y3
)
53 IDEA2
<- TT
* sum(y2
) - sum(s
)^
2
54 IDEA
<- exp(IDEA1
/ IDEA2
)